Algebra Practice Test

To find the value of x in the given system of equations, we first need to solve the equations simultaneously. The first equation is \(3x - 3y = 3\). This can be simplified by dividing the entire equation by 3: \[ x - y = 1 \quad \text{(Equation 1)} \] Next, we take the second equation, \(x - 5y = -3\) (Equation 2). Now, we can express \(x\) from Equation 1: \[ x = y + 1 \] We can substitute this expression for \(x\) into Equation 2: \[ (y + 1) - 5y = -3 \] Combining like terms gives: \[ y + 1 - 5y = -3 \] This simplifies to: \[ -4y + 1 = -3 \] Subtracting 1 from both sides results in: \[ -4y = -4 \] Dividing both sides by -4 provides us with the value of \(y\): \[ y = 1 \] Now that we have the value of \(y\