Algebra Practice Test

Question: 1 / 400

Find the value of x that satisfies 6x - 3 = 3x + 9.

x = 1

x = 2

x = 3

x = 4

To solve the equation \( 6x - 3 = 3x + 9 \), we need to isolate \( x \).

1. Start by moving all terms involving \( x \) to one side and constants to the other side. We can subtract \( 3x \) from both sides:

\[

6x - 3x - 3 = 9

\]

This simplifies to:

\[

3x - 3 = 9

\]

2. Next, add 3 to both sides to move the constant:

\[

3x - 3 + 3 = 9 + 3

\]

This simplifies to:

\[

3x = 12

\]

3. Finally, divide each side by 3 to solve for \( x \):

\[

x = \frac{12}{3} = 4

\]

Thus, the value of \( x \) that satisfies the equation \( 6x - 3 = 3x + 9 \) is 4. This indicates that when you substitute \( x = 4 \) back into the original

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